0.0	50.0	P	fracture, assume = S44E:21 at 10624'	{RTriangle	12	-1	0	0	0	RGB[64,0,64]	RGB[0,0,0]}
130.0	85.0	P	fracture	{Triangle	12	-1	0	0	0	RGB[0,0,255]	RGB[0,0,0]}
130.0	85.0	P	as the above fracture	{Triangle	12	-1	0	0	0	RGB[0,0,255]	RGB[0,0,0]}
